给定一个字符串：
"🍰天才小团团 26.6K 魅力值 惠子不在 24.7K 魅力值 🍰小天才团团～ 26.7K"
请编写一个函数，将它输出成指定的格式：
1 🍰小天才团团～ 26.7K
2 🍰天才小团团 26.6K
3 惠子不在 24.7K
题目难度：简单
题目来源：叶开
def solution(s: str) -> str:
# your code
before = "🍰天才小团团 26.6K 魅力值 惠子不在 24.7K 魅力值 🍰小天才团团～ 26.7K"
after = """
1 🍰小天才团团～ 26.7K
2 🍰天才小团团 26.6K
3 惠子不在 24.7K
"""
assert solution(before) == after
def solution(s: str) -> str:
after_list = []
for w in [i for i in s.split('K') if len(i) > 0]:
salary = float(w.split(';')[-1])
w = w.replace('魅力值', '')
w = w.replace('
', ' ')
if w.startswith(' ;'):
w = w[3:]
if ';' + str(salary) in w:
w = w.replace(';' + str(salary), str(salary))
after_list.append((salary, w))
after_list = sorted(after_list, key=lambda x: x[0])[::-1]
return '\n' + '\n'.join([str(after_list.index(s) + 1) + ' ' + s[1] + 'K' for s in after_list]) + '\n'
before = "🍰天才小团团 26.6K 魅力值 惠子不在 24.7K 魅力值 🍰小天才团团～ 26.7K"
after = """
1 🍰小天才团团～ 26.7K
2 🍰天才小团团 26.6K
3 惠子不在 24.7K
"""
assert solution(before) == after
好无聊的题！
from operator import itemgetter
def solution(s: str) -> str:
result, str_res = [], '\n'
result.append(';'.join(itemgetter(0, -1)(s.split(';', s.count(';') - 1))).replace(' ', ' '))
result.append(s.split(' ')[0].replace(' ', ' '))
result.append(' '.join(s.split(' ')[1].split(' ')[1:]))
return '\n' + ''.join([f"{index + 1} {line}\n" for index, line in enumerate(result)])
before = "🍰天才小团团 26.6K 魅力值 惠子不在 24.7K 魅力值 🍰小天才团团～ 26.7K"
after = """
1 🍰小天才团团～ 26.7K
2 🍰天才小团团 26.6K
3 惠子不在 24.7K
"""
assert solution(before) == after
搞了半天才发现是头尾没加换行
def solution(s: str) -> str:
list1 = s.split('魅力值 ')
list1 = [i.replace(' ', ' ').strip() for i in list1 if ' ' in i]
return '\n' + '1 ' + list1[2] + '\n' + '2 ' + list1[0] + '\n' + '3 ' + list1[1] + '\n'
before = "🍰天才小团团 26.6K 魅力值 惠子不在 24.7K 魅力值 🍰小天才团团～ 26.7K"
after = """
1 🍰小天才团团～ 26.7K
2 🍰天才小团团 26.6K
3 惠子不在 24.7K
"""
assert solution(before) == after
def solution(s: str) -> str:
data_list = s.replace("魅力值 ", '').replace(" ", ' ').split(
"K") # ['🍰天才小团团 26.6', ' 惠子不在 24.7', ' 🍰小天才团团～ 26.7', '']
data_list_2 = ''.join(data_list).split(' ') # ['🍰天才小团团', '26.6', '惠子不在', '24.7', '🍰小天才团团～', '26.7']
data_dict = {} # {'🍰天才小团团': '26.6', '惠子不在': '24.7', '🍰小天才团团～': '26.7'}
for i in range(0, len(data_list_2), 2):
data_dict[data_list_2[i]] = data_list_2[i + 1]
data = sorted(data_dict.items(), key=lambda v: v[1],
reverse=True) # [('🍰小天才团团～', '26.7'), ('🍰天才小团团', '26.6'), ('惠子不在', '24.7')]
after = []
for i in range(len(data)):
after.append(str(i + 1) + ' ' + data[i][0] + ' ' + data[i][1] + 'K')
return '\n' + '\n'.join(after) + '\n'
before = "🍰天才小团团 26.6K 魅力值 惠子不在 24.7K 魅力值 🍰小天才团团～ 26.7K"
print(solution(before))
after = """
1 🍰小天才团团～ 26.7K
2 🍰天才小团团 26.6K
3 惠子不在 24.7K
"""
assert solution(before) == after
Shell
echo "🍰天才小团团 26.6K 魅力值 惠子不在 24.7K 魅力值 🍰小天才团团～ 26.7K" | grep -o "[^ ]*" | sed "s/ / /g" | sed "s/魅力值 //g" | sort -k 2 -r