【每日一题1008】寻找自恋数字

兴趣爱好交流 每日一题
1

:woman_mage: 「自恋数字」表示的是一个正整数，它的字面值刚好等于其每个组成数字按照总个数的幂次方的总和。给定一个数字，请编写一个函数判断它是否是“自恋数字”。
示例：
输入：153，输出：True。
解析：因为它一共由1,5,3这3个数字组成，13 + 53 +33 = 1+125+27 = 153。

题目难度：简单
题目来源：codewars

def narcissistic(num: int) -> bool:
    pass

assert narcissistic(7) is True
assert narcissistic(371) is True
assert narcissistic(122) is False
assert narcissistic(4887) is False
2 
def narcissistic(num: int) -> bool:
    nar_sum = 0
    for i in str(num):
        nar_sum += int(i)**len(str(num))
    return nar_sum == num


assert narcissistic(7) is True
assert narcissistic(371) is True
assert narcissistic(122) is False
assert narcissistic(4887) is False
3

import math
def narcissistic(num: int) → bool:
total = 0
for i in str(num):
total += math.pow(int(i),len(str(num)))
return total == num

assert narcissistic(7) is True
assert narcissistic(371) is True
assert narcissistic(122) is False
assert narcissistic(4887) is False

4 
def narcissistic(num: int) -> bool:
    # 获取数字总个数
    n = len(str(num))
    # 将每个数字按照数字总个数的幂次方进行运算
    list_num = [int(v)**n for v in str(num)]
    # 计算列表所有元素的总和
    sum_num = sum(list_num)
    # 将计算的总和与传入的数字对比
    # 相等则为「自恋数字」
    return sum_num == num

assert narcissistic(7) is True
assert narcissistic(371) is True
assert narcissistic(122) is False
assert narcissistic(4887) is False
5 
def narcissistic(num: int) -> bool:
    x=str(num)
    l=len(x)
    s=0
    for i in x:
        s+=int(i)**l
    if s==num:
        return True
    else:
        return False

assert narcissistic(7) is True
assert narcissistic(371) is True
assert narcissistic(122) is False
assert narcissistic(4887) is False