【每日一题20220620】最佳算式

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1

:mage:‍ 给定3个数字a,b,c，我们的任务是使用+,*和()将它们组成数学算式。请编写一个函数，找出最终得数最大的那个算式。

【示例】
输入：1,2,3
输出：9
解释：根据数字1,2,3，可以组成1 * (2 + 3) = 5，或者1 * 2 * 3 = 6，或者1 + 2 * 3 = 7，以及(1 + 2) * 3 = 9，所以其中最大得数是9。

题目难度：简单
题目来源：codewars-Expressions Matter

def solution(a:int, b:int, c:int)-> int:
    # your code here

assert solution(1,2,3) == 9
assert solution(2,1,2) == 6
assert solution(3,5,7) == 105
2 
def solution(a: int, b: int, c: int) -> int:
    return max([a * (b + c), a * b * c, a + b * c, (a + b) * c])
3 
def solution(a: int, b: int, c: int) -> int:
	# your code here
	return max([a * (b + c), a * b * c, a + b * c, (a + b) * c, a + b + c])

assert solution(1, 2, 3) == 9
assert solution(1, 1, 1) == 3
assert solution(2, 1, 2) == 6
assert solution(3, 5, 7) == 105
4 
def solution(a:int, b:int, c:int)-> int:

    return max([a * (b + c), (a + b) * c, a * b * c, a * b + c, a + b * c, a + b + c])


if __name__ == '__main__':
    assert solution(1,2,3) == 9
    assert solution(2,1,2) == 6
    assert solution(3,5,7) == 105
5 
def solution(a:int, b:int, c:int)-> int:
    return max([a*(b+c),a*b*c,a+b*c,(a+b)*c])
6 
def solution(a:int, b:int, c:int)-> int:
    return max([a*b*c,(a+b)*c,a*(b+c),a+b*c,a*b+c,a+b+c])

assert solution(1,2,3) == 9
assert solution(2,1,2) == 6
assert solution(3,5,7) == 105
7 
def solution(a:int, b:int, c:int)-> int:
    # your code here
    return max([(a + b + c), a * (b + c), (a + b) * c, (a + c) * b, (a * b * c)])


assert solution(1,2,3) == 9
assert solution(2,1,2) == 6
assert solution(3,5,7) == 105
8 
def expression_matter(a, b, c):
    if 1 not in {a,b,c}:
        return a*b*c
    return max(a * (b + c),(a + b) * c,a + b + c)
9 
def solution(a:int, b:int, c:int)-> int:
    int_list=sorted([a,b,c],reverse=False)
    if 1 in int_list:
        return (int_list[0]+int_list[1])*int_list[2]
    else:
        return int_list[0]*int_list[1]*int_list[2]

assert solution(1,2,3) == 9
assert solution(2,1,2) == 6
assert solution(3,5,7) == 105