a b c d e f g h i j k l m
1 2 3 4 5 6 7 8 9 10 11 12 13
n o p q r s t u v w x y z
14 15 16 17 18 19 20 21 22 23 24 25 26
然后，给定一个加密后的数字列表和一个密钥数字，请编写一个函数，将每个数字，按顺序减去对应位置上的密钥数字，最后返回加密前的字符串文本。
【示例】[ 20, 12, 18, 30, 21], 1939"scout"
20 12 18 30 21
- 1 9 3 9 1
---------------------------
19 3 15 21 20
s c o u t
题目难度：中等Codewars-Digital cypher2
def solution(nums: list, key: int)-> str:
# your code here
assert solution([ 20, 12, 18, 30, 21],1939) == "scout"
assert solution([ 14, 10, 22, 29, 6, 27, 19, 18, 6, 12, 8], 1939) == "masterpiece"
joyoko
2022 年5 月 30 日 02:58
2
def solution(nums: list, key: int) -> str:
return "".join([chr(int(i)-int(j)+96) for i, j in zip(nums, (str(key) * ((len(nums) // len(str(key)) + 1)))[:len(nums)])])
assert solution([ 20, 12, 18, 30, 21],1939) == "scout"
assert solution([ 14, 10, 22, 29, 6, 27, 19, 18, 6, 12, 8], 1939) == "masterpiece"
def solution(nums: list, key: int)-> str:
length = len(str(key))
str1 = ""
for i in range(len(nums)):
tmp = chr(nums[i] - int(str(key)[i%length]) + 96)
str1 = str1 + tmp
return str1
assert solution([ 20, 12, 18, 30, 21],1939) == "scout"
assert solution([ 14, 10, 22, 29, 6, 27, 19, 18, 6, 12, 8], 1939) == "masterpiece"
def solution(ls,key):
key_ls = [int(i) for i in list(str(key))]
length = len(key_ls)
total = ""
for i in range(len(ls)):
total += chr(96+ls[i]-key_ls[i%length])
return total
def encode(message,key):
return ''.join([chr(value+96-int(str(key)[index%len(str(key))])) for index,value in enumerate (message)])
def solution(nums: list, key: int)-> str:
# your code here
for i in range(len(nums)):
nums[i] -= int(str(key)[i%len(str(key))])
return "".join([chr(96+i) for i in nums])
assert solution([ 20, 12, 18, 30, 21],1939) == "scout"
assert solution([ 14, 10, 22, 29, 6, 27, 19, 18, 6, 12, 8], 1939) == "masterpiece"
HLK
2022 年5 月 31 日 02:22
7
def solution(nums: list, key: int)-> str:
dict_data = dict(zip([i for i in range(1, 27)], [chr(i) for i in range(97, 123)]))
key_new = [int(i) for i in str(key) * (len(nums) // len(str(key))) + str(key)[0:len(nums) % len(str(key))]]
result = "".join([dict_data.get(i) for i in [nums[i]-key_new[i] for i in range(len(nums))]])
return result
assert solution([ 20, 12, 18, 30, 21],1939) == "scout"
assert solution([ 14, 10, 22, 29, 6, 27, 19, 18, 6, 12, 8], 1939) == "masterpiece"
def solution(nums: list, key: int) -> str:
key_str = (str(key) * ((len(nums) // len(str(key)) + 1)))[:len(nums)]
key_int = [int(key_str[i]) for i in range(len(key_str))]
return ''.join([chr(nums[i] - key_int[i] + 96) for i in range(len(nums))])
assert solution([20, 12, 18, 30, 21], 1939) == "scout"
assert solution([14, 10, 22, 29, 6, 27, 19, 18, 6, 12, 8], 1939) == "masterpiece"
数字密码的规则首先是将字母表中的每个字母进行编号：