【每日一题20220425】旋转罗盘

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21 
def solution(direction: str, degree: int) -> str:
    direction_list = ["N", "NE", "E", "SE", "S", "SW", "W", "NW"]
    if degree % 45 == 0:
        res_index = (degree // 45 + direction_list.index(direction)) % 8
        return direction_list[res_index]
    else:
        return False


assert solution("S", 180) == "N"
assert solution("SE", -45) == "E"
assert solution("W", 495) == "NE"
22 
def solution(direction: str, degree: int)-> str:
	compass=["N","NE","E","SE","S","SW","W","NW"]
	n=degree/45  #需要移动位移长度
	index_dir=compass.index(direction)  ##目前字符所在的索引位置是
	mo=int(index_dir+n)  ##移动后得索引
	if mo<8:
		return compass[mo]
	else:
		return compass[int(mo%8)]
23 
def solution(direction: str, degree: int)-> str:
    dict={"N":0,"NE":45,"E":90,"SE":135,"S":180,"SW":225,"W":270,"NW":315}
    degree_res = dict[direction] + degree
    while degree_res<0 or degree_res>=360:
        if degree_res<0:
            degree_res+=360
        else:
            degree_res-=360
    return [i for i in dict.keys() if dict[i]==degree_res][0]

assert solution("S", 180) == "N"
assert solution("SE", -45) == "E"
assert solution("W",  495) == "NE"