回文是指一段数字或者文本，正着读和倒着读都是相同的，例如2002，110011都是回文数字。请编写一个函数，接收2个数字n和m，找出大于数字n的m个有效回文数字，以列表的格式返回。如果n本身也是回文数字，那么也算其中一个。单个数字不被视为回文数字。
【示例】
输入：6, 4
输出：[11, 22, 33, 44]
解释：6自身不算回文数字，继续往后找。直到找到11、22、33和44，一共4个有效的回文数字为止。
题目难度：中等
题目来源：CodeWars-Numerical Palindrome #1.5
def solution(n: int, m: int)-> list:
# your code here
assert solution(6, 4) == [11, 22, 33, 44]
assert solution(59, 3) == [66, 77, 88]
assert solution(101, 2) == [101, 111]
def solution(n: int, m: int)-> list:
result_list = []
def get_num(num):
if len(str(num))<=1:
return False
if str(num) == str(num)[::-1]:
return num
while n:
if len(result_list)==m:
return result_list
if get_num(n):
result_list.append(n)
n += 1
assert solution(6, 4) == [11, 22, 33, 44]
assert solution(59, 3) == [66, 77, 88]
assert solution(101, 2) == [101, 111]
def solution(n: int, m: int)-> list:
# your code here
res_list = []
while n:
if n < 10:
n += 1
continue
if n == int(str(n)[::-1]):
res_list.append(n)
if len(res_list) == m:
break
n += 1
return res_list
assert solution(6, 4) == [11, 22, 33, 44]
assert solution(59, 3) == [66, 77, 88]
assert solution(101, 2) == [101, 111]
def solution(n: int, m: int)-> list:
# your code here
value =
i = 0
while len(value) < m:
k = n + i
if k == int((str(k)[::-1])) and k > 10:
value.append(k)
i += 1
return value
assert solution(6, 4) == [11, 22, 33, 44]
assert solution(59, 3) == [66, 77, 88]
assert solution(101, 2) == [101, 111]
def solution(n, m):
# your code here
lt = []
while n:
if n < 9:
n += 1
continue
if str(n) == str(n)[::-1]:
lt.append(n)
if len(lt) == m :
return lt
n += 1
assert solution(6, 4) == [11, 22, 33, 44]
assert solution(59, 3) == [66, 77, 88]
assert solution(101, 2) == [101, 111]
def solution(n: int, m: int) -> list:
r = []
while True:
if n == int(str(n)[::-1]) and n > 10:
r.append(n)
if len(r) == m:
return r
n += 1
assert solution(6, 4) == [11, 22, 33, 44]
assert solution(59, 3) == [66, 77, 88]
assert solution(101, 2) == [101, 111]
def solution(n:int, m:int):
setDatas =
while n:
if len(setDatas) == 3:
return setDatas
if str(n) == str(n)[::-1]:
setDatas.append(n)
n += 1
assert solution(6, 4) == [11, 22, 33, 44]
def solution(n: int, m: int)-> list:
result=list()
while True and len(result)>m:
if n>9 and str(n)[::-1]==str(n):
result.append(n)
n+=1
else:
n+=1
return result
def solution(n: int, m: int)-> list:
list_num=[]
while len(list_num)<m:
if n<10:
n=10
if n==int((str(n)[::-1])):
list_num.append(n)
n=n+1
return list_num
def solution(n, m):
a = []
while len(a) < m:
if n > 10:
if n == int(str(n)[::-1]):
a.append(n)
n = n + 1
return a
def solution(n: int,m: int) → list:
lst =
while True:
if n>10 and str(n) == str(n)[::-1]:
lst.append(n)
n = n+1
if len(lst) == m:
break
return lst
def fun(num: int) -> bool:
nums_str = str(num)
if nums_str == ''.join(reversed(nums_str)):
return True
else:
return False
def solution(n: int, m: int) -> list:
i = 0
result = []
while i < m:
if n < 10:
n = 10
if fun(n):
i += 1
result.append(n)
n += 1
return result
assert solution(6, 4) == [11, 22, 33, 44]
assert solution(59, 3) == [66, 77, 88]
assert solution(101, 2) == [101, 111]
def solution(n: int, m: int) → list:
# your code here
count = 0
reslut =
while True:
if str(count) == str(count)[::-1] and len(str(count)) > 1 and count >= n:
# print(count)
reslut.append(count)
count += 1
if len(reslut) >= m:
return reslut
else:
count += 1
def solution(n: int, m: int) -> list:
result_list = []
def get_num(num):
if len(str(num)) <= 1:
return False
if str(num) == str(num)[::-1]:
return num
while n:
if len(result_list) == m:
return result_list
if get_num(n):
result_list.append(n)
n += 1