已知度数是一个非负浮点数，并且满足：1度= 1小时，1分钟=60秒钟。请编写一个函数convert，接收一个度数值degree，以列表的格式返回它所表示的度数、分钟数和秒数。
备注：所有的度数/分钟数、秒数均取整数部分。
示例：
输入：50，输出：[50]。
输入：40.567，输出[40, 34, 1]。因为0.567度是34.02分钟，取34；0.02分钟是1.2，取1。题目难度：简单
题目来源：codewars
def convert(degree: int) -> list:
pass
assert convert(50) == [50, 0, 0]
assert convert(80.5) == [80, 30 ,0]
assert convert(40.567) == [40, 34, 1]
# 方法一
def convert(degree):
list=[]
str_degress=str(degree)
if str_degress.count(".")==0:
list=[degree,0,0]
return list
else:
a=str(degree).split(".")
length=len(a[1])
list.append(a[0])
# 求分
m=round(int(a[1])/10**length*60,2)
b=str(m).split(".")
list.append(b[0])
# 求秒
s=int(int(b[1])/10**len(b)*60)
list.append(s)
return list
# 方法二
import math
def convert1(degree):
list=[]
list1=math.modf(degree)
list.append(int(list1[1]))
a=list1[0]*60
list2=math.modf(a)
list.append(int(list2[1]))
s=int(list2[0]*60)
list.append(s)
return list
def convert(degree: int) -> list:
if degree==int(degree):
return [int(degree),0,0]
s = (degree-int(degree))*60
if s == int(s):
return [int(degree),int(s),0]
return [int(degree),int(s),int((s-int(s))*60)]
def convert(degree) -> list:
min = (degree - int(degree)) * 60
second = (min - int(min)) * 60
return [int(degree),int(min),int(second)]
public ArrayList<Integer> convert(Double d){
ArrayList<Integer> result = new ArrayList<>();
BigDecimal du = new BigDecimal(d.toString());
result.add(d.intValue());
BigDecimal subtract = du.subtract(new BigDecimal(d.intValue()));
int fen = subtract.multiply(new BigDecimal(60)).intValue();
result.add(fen);
BigDecimal subtract1 = subtract.multiply(new BigDecimal(60)).subtract(new BigDecimal(fen));
int miao = subtract1.multiply(new BigDecimal(60)).intValue();
result.add(miao);
return result;
}
@Test
public void TestConvert(){
assert convert(50.0).equals(Arrays.asList(50,0,0));
assert convert(80.5).equals(Arrays.asList(80,30,0));
assert convert(40.567).equals(Arrays.asList(40,34,1));
}
def convert(degree: float) -> list:
a = degree - int(degree)
b = (a - int(a)) * 60 if a > 0 else 0
c = (b - int(b)) * 60 if b > 0 else 0
return [int(degree),int(b),int(c)]
assert convert(50) == [50, 0, 0]
assert convert(80.5) == [80, 30 ,0]
assert convert(40.567) == [40, 34, 1]