d={'A':10,'B':11,'C':"8"}
按value值排序后 {'C':"8",'A':10,'B':11}
题解:
d={'A':10,'B':11,'C':"8"}
def order(inp_dict):
return dict(sorted(inp_dict.items(),key=lambda x:int(x[1])))
assert {'C':"8",'A':10,'B':11} == order(d)
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def order_by_value(d:dict):
""" 根据value值升序排列"""
# d = {'D': 12, 'B': 11, 'C': "8"}
return dict(sorted(d.items(), key=lambda x:int(x[1])))
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def sortFunc(dictData, result={}):
L=list(dictData.values())
for i in range(len(L)):
L[i] = int(L[i])
L.sort()
for item in L:
for key in list(dictData.keys()):
if int(dictData[key]) == item:
result[key] = dictData[key]
return result
assert sortFunc({'A':10,'B':11,'C':"8"}) == {'C':"8",'A':10,'B':11}