【每日一题20220621】点赞点踩

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1

:mage:‍ 在一些社交媒体App的博文中，会提供:+1:【点赞】和:-1:【点踩】的按钮，用来表达观众的态度。默认按钮的默认值都是空的。具体规则如下：点赞和点踩是互斥的，同一时间只能赞或者踩；连续点赞或者点踩按钮两次会在高亮和取消之间翻转。 请编写一个函数，接收用户的动作列表，返回最终的态度结果。如果是点赞则返回“赞”，如果是点踩则返回“踩”，如果既没有“赞”或者“踩”则返回无。

【示例】
输入：["踩", "赞"]
输出：赞
解释：用户首先点了踩，然后点了赞，最终这篇博文收到了赞。

题目难度：简单
题目来源：codewars-Likes Vs Dislikes

def solution(words:list)-> str:
    # your code here

assert solution(["踩", "赞"]) == "赞"
assert solution(["赞", "赞"]) == "无"
assert solution(["踩"]) == "踩"
2 
def solution(words: list) -> str:
    # your code here
    result = "无"
    for i in words:
        result = "无" if result == i else i
    return result


assert solution(["踩", "赞"]) == "赞"
assert solution(["赞", "赞"]) == "无"
assert solution(["踩"]) == "踩"
3 
def solution(words:list)-> str:
    word = words[-1]
    count = words.count(word)
    if count % 2 == 0:
        return "无"
    return word


if __name__ == '__main__':
    assert solution(["踩", "赞"]) == "赞"
    assert solution(["赞", "赞"]) == "无"
    assert solution(["踩"]) == "踩"
4 
def solution(words:list)-> str:
    tmp = "无"
    for i in words:
        tmp = "无" if i == tmp else i
    return tmp


assert solution(["踩", "赞"]) == "赞"
assert solution(["赞", "赞"]) == "无"
assert solution(["踩"]) == "踩"
5 
def solution(words:list)-> str:
    return '无' if words[1:]==words[:-1] and len(words)>1 else words[-1]
6 
def solution(words:list)-> str:
    return '无' if len(set(words))==1 and len(words)>1 else words[-1]
7 
def solution(words: list) -> str:
    # your code here
    length = len(words)
    if length == 1:
        return words[0]
    elif length >= 2 and words[-1] != words[-2]:
        return words[-1]
    else:
        return '无'
10

assert solution([“赞”, “赞”]) == “无”

这条case执行不同通过

11

列表

12 
def solution(words: list) -> str:
    # your code here
    result = "无"
    for i in words:
        #     if result != i:
        #         result = i
        #     elif result == i:
        #         result = "无"
        result = "无" if result == i else i
    return result


assert solution(["踩", "赞"]) == "赞"
assert solution(["赞", "赞"]) == "无"
assert solution(["踩"]) == "踩"
assert solution(["踩", "赞", "赞"]) == "无"
13 
def solution0727(words:list)-> str:
    result="无"
    for i in range(len(words)):
        if words[i] != result:
            result=words[i]
        else:
            result = "无"
    return result